姬長信(Redy)

Cython,Python和KeyboardInterrupt被忽略了


有没有办法根据嵌入在Cython扩展中的循环中断(Ctrl C)Python脚本?

我有以下python脚本:

def main():

    # Intantiate simulator
    sim = PySimulator()
    sim.Run()

if __name__ == "__main__":
    # Try to deal with Ctrl+C to abort the running simulation in terminal
    # (Doesn't work...)
    try:
        sys.exit(main())
    except (KeyboardInterrupt, SystemExit):
        print '/n! Received keyboard interrupt, quitting threads./n'

这将运行一个循环,它是C Cython扩展的一部分.
然后,在按下Ctrl C的同时,抛出KeyboardInterrupt但忽略,程序一直持续到模拟结束.

我找到的工作是通过捕获SIGINT信号来处理扩展内的异常:

#include 
#include 

static void handler(int sig)
{
  // Catch exceptions
  switch(sig)
  {
    case SIGABRT:
      fputs("Caught SIGABRT: usually caused by an abort() or assert()/n", stderr);
      break;
    case SIGFPE:
      fputs("Caught SIGFPE: arithmetic exception, such as divide by zero/n",
            stderr);
      break;
    case SIGILL:
      fputs("Caught SIGILL: illegal instruction/n", stderr);
      break;
    case SIGINT:
      fputs("Caught SIGINT: interactive attention signal, probably a ctrl+c/n",
            stderr);
      break;
    case SIGSEGV:
      fputs("Caught SIGSEGV: segfault/n", stderr);
      break;
    case SIGTERM:
    default:
      fputs("Caught SIGTERM: a termination request was sent to the program/n",
            stderr);
      break;
  }
  exit(sig);

}

然后 :

signal(SIGABRT, handler);
signal(SIGFPE,  handler);
signal(SIGILL,  handler);
signal(SIGINT,  handler);
signal(SIGSEGV, handler);
signal(SIGTERM, handler);

我不能用Python,或者至少从Cython中做这项工作吗?当我即将在Windows / MinGW下移植我的扩展时,我希望能有一些不那么具体的Linux.